ind=ind+3
enddo
do i=nnt,nct
- if (itype(i).ne.10 .and. itype(i).ne.21) then
+ if (itype(i).ne.10 .and. itype(i).ne.ntyp1) then
do j=1,3
d_t_work(ind+j)=d_t(j,i+nres)
enddo
ind=ind+3
enddo
do i=nnt,nct
- if (itype(i).ne.10 .and. itype(i).ne.21) then
+ if (itype(i).ne.10 .and. itype(i).ne.ntyp1) then
do j=1,3
friction(j,i+nres)=fric_work(ind+j)
enddo
do j=1,3
ff(j)=ff(j)+force(j,i)
enddo
- if (itype(i+1).ne.21) then
+ if (itype(i+1).ne.ntyp1) then
do j=1,3
stochforc(j,i)=stochforc(j,i)+force(j,i+nres+1)
ff(j)=ff(j)+force(j,i+nres+1)
stochforc(j,0)=ff(j)+force(j,nnt+nres)
enddo
do i=nnt,nct
- if (itype(i).ne.10 .and. itype(i).ne.21) then
+ if (itype(i).ne.10 .and. itype(i).ne.ntyp1) then
do j=1,3
stochforc(j,i+nres)=force(j,i+nres)
enddo
ind=ind+3
enddo
do i=nnt,nct
- if (itype(i).ne.10 .and. itype(i).ne.21) then
+ if (itype(i).ne.10 .and. itype(i).ne.ntyp1) then
do j=1,3
stochforcvec(ind+j)=stochforc(j,i+nres)
enddo
c Load the friction coefficients corresponding to side chains
m=nct-nnt
ind=0
- gamsc(21)=1.0d0
+ gamsc(ntyp1)=1.0d0
do i=nnt,nct
ind=ind+1
ii = ind+m